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The period of the earth around the sun is 1 year and its distance is 150 million km from the sun. An asteroid in a circular orbit around the sun is at a distance 440 million km from the sun. What is the period of the asteroid’s orbit? Answer in units of year.

Answer :

Answer:

5.024 years

Explanation:

T1 = 1 year

r1 = 150 million km

r2 = 440 million km

let the period of asteroid orbit is T2.

Use Kepler's third law

T² ∝ r³

So,

[tex]\left ( \frac{T_{2}}{T_{1}} \right )^2=\left ( \frac{r_{2}}{r_{1}} \right )^3[/tex]

[tex]\left ( \frac{T_{2}}{1} \right )^2=\left ( \frac{440}{150} \right )^3[/tex]

T2 = 5.024 years

Thus, the period of the asteroid's orbit is 5.024 years.

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