Answer :
Horizontal component of vector A: 5.0 cm
Vertical component of vector A: 8.7 cm
Explanation:
The horizontal and vertical components of a vector on the cartesian plane are calculated as follow:
[tex]v_x = v cos \theta\\v_y = v sin \theta[/tex]
where
[tex]v_x[/tex] is the horizontal component
[tex]v_y[/tex] is the vertical component
v is the magnitude of the vector
[tex]\theta[/tex] is the angle between the direction of the vector and x-axis
In this problem, we have
v = 10.0 cm is the magnitude of vector A
[tex]\theta=60.0^{\circ}[/tex] is the angle of its direction with the x-axis
Applying the equations, we find
[tex]v_x = (10.0)(cos 60)=5.0 cm[/tex]
[tex]v_y = (10.0)(sin 60)=8.7 cm[/tex]
Learn more about vector components:
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