Answer :
Answer:
[tex]111\ grams\ of\ zinc[/tex]
Step-by-step explanation:
Let
x -----> grams of zinc
y ----> grams of copper
we know that
[tex]\frac{x}{y}=\frac{3}{17}[/tex] -----> equation A
For y=629 grams of copper
substitute in the equation A and solve for x
[tex]\frac{x}{629}=\frac{3}{17}[/tex]
[tex]x=\frac{3}{17}(629)[/tex]
[tex]x=111\ grams\ of\ zinc[/tex]