A flat, rectangular coil consisting of 60 turns measures 23.0 cm by 31.0 cm . It is in a uniform, 1.20-T, magnetic field, with the plane of the coil parallel to the field. In 0.210 s , it is rotated so that the plane of the coil is perpendicular to the field.Part A What is the change in the magnetic flux through the coil due to this rotation?Part B Find the magnitude of the average emf induced in the coil during this rotation.

Answer :

Answer:25.23 V

Explanation:

Given

no of turns [tex]N=60 turns[/tex]

Magnetic Field [tex]B=1.2 T[/tex]

Area of rectangular coil [tex]A=23\times 31=713 cm^2\approx 0.0713m^2[/tex]

Change in magnetic Flux is given by

[tex]\Delta \phi =BA\cos \theta [/tex]

[tex]\Delta \phi =1.2\times 0.0736\cos 0=0.08832 V-s[/tex]

(b)Emf induced change in Flux with respect to time and it can be given by

[tex]E=-N\frac{\mathrm{d} \phi }{\mathrm{d} t}[/tex]

[tex]E=-60\times \frac{0.08832}{0.21}[/tex]

[tex]E=-25.23 V[/tex]

The magnitude of emf induced is [tex]25.23 V[/tex]

     

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