Answered

A rocket in space is launched into space from the rest position. If the acceleration of the rocket is 5.25 m/s^2, find how far the rocket moves in 5 minutes?

Answer :

skyluke89

The displacement of the rocket is 236 km

Explanation:

The motion of the rocket is a uniformly accelerated motion (= constant acceleration), therefore we can use the following suvat equation:

[tex]s=ut+\frac{1}{2}at^2[/tex]

where

u is the initial velocity

s is the displacement

t is the time

a is the acceleration

For the rocket in this problem,

u = 0 (the rocket starts from rest)

[tex]a=5.25 m/s^2[/tex] is the acceleration

[tex]t=5 min \cdot 60 = 300 s[/tex] is the time interval

Substituting, we find the displacement of the rocket:

[tex]s=0+\frac{1}{2}(5.25)(300)^2=2.36\cdot 10^5 m = 236 km[/tex]

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