find the area of regular polygon. can anyone help me been stuck with this for hours

Answer:
Step-by-step explanation:
Area of hexagon given apothem. (The line that is 5 rad 3)
The apothem is perpendicular to the side of the hexagon, forming a triangle with the corner of the hexagon. The angle measurement of the corner is 60 degrees because the angle measurement of any interior angle of a regular hexagon is 120. this means that the imaginary triangle connecting the apothem to the closest corner and that to the center is a 30-60-90 triangle.
The sides of a 30-60-90 triangle are
a (the shortest side)= x
b (The longer leg/ apothem in this scenario)= x rad 3
c (hypotenuse)=2x
a=5
b=5 rad 3
c=10
2a= side length = 10
using the formula for hexagon area
A =((3 rad 3)/2) s^2
where s is the side
(3 rad 3)/2 x 100
A=259.81
Answer:
The answer to your question is 259.8 cm²
Step-by-step explanation:
Formula
Area = [tex]\frac{Perimeter x A}{2}[/tex]
See the picture below
1.- Find the perimeter
From the right triangle find the lenght of one side
tan 30° = [tex]\frac{x}{5\sqrt{3} }[/tex]
x = [tex]5\sqrt{3} tan30°[/tex]
tan 30° = [tex]\frac{1}{\sqrt{3} }[/tex]
Then
x = [tex]5\frac{\sqrt{3} }{\sqrt{3} }[/tex]
x = 5
lenght of a side = 2x = 2(5) = 10
Perimeter = 10 x 6
= 60
2.- Find the area
[tex]Area = \frac{60 x 5\sqrt{3} }{2}[/tex]
[tex]Area = 30x5\sqrt{3}[/tex]
[tex]Area = 150\sqrt{3}[/tex]
[tex]Area = 259.8 cm^{2}[/tex]