The volume of 0.496 M HCl required to neutralize 20.0 mL of 0.809 M sodium hydroxide is 32.62mL.
FINDING CONCENTRATION:
- The volume of an acid or base in a titration reaction can be calculated using the following expression:
CaVa = CbVb
Where;
- Ca = concentration of acid (M)
- Cb = concentration of base (M)
- Va = volume of acid (mL)
- Vb = volume of base (mL)
The parameters given in this question are as follows:
- Ca = 0.496 M
- Cb = 0.809 M
- Va = ?
- Vb = 20.0 mL
0.496 × Va = 0.809 × 20
0.496Va = 16.18
Va = 16.18 ÷ 0.496
Va = 32.62mL
Therefore, the volume of 0.496 M HCl required to neutralize 20.0 mL of 0.809 M sodium hydroxide is 32.62mL.
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