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Use the given information to find the p​-value. ​Also, use a 0.05 significance level and state the conclusion about the null hypothesis​ (reject the null hypothesis or fail to reject the null​ hypothesis). With Upper H 1 H1​: p not equals ≠ three fifths 3 5 ​, the test statistic is z equals =0.78.

Answer :

JeanaShupp

Answer: 0.4354

Step-by-step explanation:

According to the given information , we have

Significance level : [tex]\alpha=0.05[/tex]

Alternative hypothesis : [tex]H_a: p\neq\dfrac{3}{5}[/tex]

Test statistic : z= 0.78

Since the alternative hypothesis is two-tailed , so the test is a two-tailed test.

P-value for two-tailed test is given by :-

2P(Z > |z|)

= 2P(Z<|0.78|)

=2P(Z<0.78)

=2(1-P(z≤0.78))                 [∵ P(Z>z)=1- P(Z≤z)]

= 2(1-0.7823)                   [By z-value table]

=2(0.2177)

=0.4354

Hence, the required p​-value = 0.4354

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