Answer :
Answer:
The answer is [tex]9604\cdot r^{16}[/tex]
Step-by-step explanation:
2r^{2}\sqrt{7r^{4}}\cdot7\sqrt{7r^{8}}2r^{2}\sqrt{7r^{4}}\cdot7\sqrt{7r^{8}}
We Have To reduce it to simplified
[tex]\sqrt{x^2}[/tex] = [tex]x[/tex]
[tex]2r^{2} \sqrt{7}r^{2}\cdot7\sqrt{7} r^4\cdot2r^2\sqrt{7}r^{2}\cdot7\sqrt{7}r^4[/tex]
[tex]2\cdot2\cdot7\cdot7\cdot7\cdot7\cdot r^{16}[/tex]
[tex]9604\cdot r^{16}[/tex]
The answer is [tex]9604\cdot r^{16}[/tex]