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A magnetic field of 0.1 T forces a proton beam of 1.5 mA to move in a circle of radius 0.1 m. The plane of the circle is perpendicular to the magnetic field. Of the following, which is the best estimate of the work done by the magnetic field on the protons during one complete orbit of the circle?
0 J

10-22 J

10-5 J

102 J

1020 J

Answer :

boffeemadrid

Answer:

0 J

Explanation:

q = Charge of particle

v = Velocity of particle

B = Magnetic flux

dr = Displacement

Force generated by magnetic field is given by

[tex]\vec F=\vec{qv}\times \vec B[/tex]

Work done by the magnetic field is given by

[tex]dW=\vecF.\vec{dr}[/tex]

Here, the force exerted by the magnetic field is at  90° (perpendicular) to displacement so the work done is zero.

Lanuel

An estimate of the work done by the magnetic field on the protons during one complete orbit of the circle is zero (0) Joules.

How to calculate the magnetic force.

Mathematically, the magnitude of a force acting in a magnetic field is given by this formula:

[tex]F=BILsin\theta[/tex]

Where:

  • B is the magnetic field.
  • I is the current.
  • L is the length.
  • \theta is the angle.

Mathematically, the work done by a magnetic field due to a force is given by:

[tex]W=FScosq[/tex]

Note: The work done by a magnetic field due to a perpendicular force is equal to zero when the value of q is 90 degrees.

In this scenario, the force exerted by the magnetic field is perpendicular to displacement (90 degrees) and as such, the work done would be equal to zero (0) Joules.

Read more on magnetic field here: https://brainly.com/question/7802337

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