Answered

Ten days after it was launched toward Mars in December 1998, the Mars Climate Orbiter spacecraft (mass 629 kg) was 2.87×10⁶ km from the earth and traveling at 1.20×10⁴ km/h relative to the earth.At this time, what were (a) the spacecraft’s kinetic energy relative to the earth and (b) the potential energy of the earth–spacecraft system?

Answer :

Khoso123

Answer:

[tex](a)K.E=3.49*10^{9}J\\ (b)P.E=-8.73*10^{7}J[/tex]

Explanation:

Given data

mass=629 kg

[tex]distance=2.87*10^{6}km\\ v=1.20*10^{4}\frac{km}{h}\\  K.E=?\\P.E=?[/tex]

Sokution

For (a) K.E

[tex]K.E=\frac{1}{2}mv^{2}\\  as \\v=1.20*10^{4}\frac{km}{h}=3.33*10^{3}\frac{m}{s}\\    K.E=(1/2)*(629)*(3.33*10^{3})^{2}  \\K.E=3.49*10^{9}J[/tex]

For (b) P.E

[tex]P.E=\frac{-G*m(orbiter)*m(earth)}{r}\\ P.E=\frac{-(6.67*10^{-11} )*(629)*(5.97*10^{24} )}{2.89*10^{9} }\\ P.E=-8.73*10^{7}J[/tex]

Other Questions