Answer :
Answer:
The new concentration of the sodium hydroxide solution = 0.154 M
Explanation:
Considering :-
[tex]Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}[/tex]
Given that:
[tex]Molarity_{1}=0.770\ M[/tex]
[tex]Volume_{1}=10.0\ mL[/tex]
[tex]Volume_{2}=50.0\ mL[/tex]
[tex]Molarity_{2}=?[/tex]
So,
[tex]Molarity_{1}\times Volume_{1}=Molarity_{2}\times Volume_{2}[/tex]
[tex]0.770\ M\times 10.0\ mL=Molarity_{2}\times 50.0\ mL[/tex]
[tex]Molarity_2=\frac{0.770\times 10.0}{50.0}\ M=0.154\ M[/tex]
The new concentration of the sodium hydroxide solution = 0.154 M
