Answer:
Question 1:
y-2=-3(x+2) - In Point-Slope Form
y=-3x-4 - In Slope-Intercept Form
Question 2:
y-1=1/2(x+6) - In Point-Slope Form
y=1/2x+4 - In Slope-Intercept Form
Step-by-step explanation:
Attached is a picture of the point slope formula which we will be using to write the equations of these lines...
Question 1: Write the equation of the line passing through the points (0, -4) and (-2, 2).
1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):
(2--4)/(-2-0)
2) Simplify:
6/-2
3) Solve:
m=-3
4) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-2,2)]
y-2=-3(x+2)
5) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute -3 to x and 2:
y-2=-3x-6
6) Next, Add 2 to both sides: (Now it is in slope-intercept form)
y=-3x-4
Question 2: Write the equation of the line passing through the points (-6,1) and (-4,2).
1) First, we need to find the slope, or "m" of this line. Lets plug these two points into slope formula (y2-y1/x2-x1):
(2-1)/(-4--6)
2) Simplify:
m=1/2
3) Now, lets plug that slope into point-slope formula along with a set of points that were given to us [I will be using (-6,1)]
y-1=1/2(x+6)
4) Now, if you wish to write the equation of the line in slope intercept form, we will have to do some simple algebra. First, distribute 1/2 to x and 6:
y-1=1/2x+3
5) Next, add 1 to both sides: (Now it is in slope-intercept form)
y=1/2x+4
