The second side of a triangular deck is 6 feet longer than the shortest​ side, and the third side is 6 feet shorter than twice the length of the shortest side. If the perimeter of the deck is 68 ​feet,
what are the lengths of the three​ sides?
The shortest side of the deck is The second side of the deck is The third side of the deck is

Answer :

Answer:

The shortest side of the deck is 17 feet.

The second side of the deck is 23 feet.

The third side of the deck is 28 feet.

Step-by-step explanation:

Let x represent the length of shortest side of the triangular deck.

We have been given that the second side of a triangular deck is 6 feet longer than the shortest​ side, so the length of second side would be [tex]x+6[/tex].

We are also told that the third side is 6 feet shorter than twice the length of the shortest side, so the length of third side would be [tex]2x-6[/tex].

Since the perimeter of the deck is 68 ​feet, so sum of lengths of all sides of deck would be equal to 68.

[tex]x+x+6+2x-6=68[/tex]

Let us solve for x.

[tex]x+x+2x+6-6=68[/tex]

Combine like terms:

[tex]4x=68[/tex]

Divide both sides by 4:

[tex]\frac{4x}{4}=\frac{68}{4}[/tex]

[tex]x=17[/tex]

Therefore, the shortest side of the deck is 17 feet.

The length of second side would be: [tex]x+6\Rightarrow 17+6=23[/tex]

Therefore, the second side of the deck is 23 feet.

the length of third side would be: [tex]2x-6\Rightarrow 2\cdot 17-6=34-6=28[/tex]

Therefore, the third side of the deck is 28 feet.

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