Answer :
Answer:
Speed along the line joining both = 7.84 meter/second
Step-by-step explanation:
To find the rate of change of distance between the man and the car at that instant we have to find the component of speed of the car along the line joining the car and the person .
The person is 10 metre east of intersection and the car is 24 metres north of the intersection.Thus it forms a right triangle with sides of length 10 and 24.
Then the length of other side is x.
By Pythagoras theorem ,
x = [tex]\sqrt{(24)^{2}+10^{2} }[/tex]
x = 26 meters
Speed along north direction = 13 meters/second
Speed along the line joining both = [tex] 13\times cos(p)[/tex]
= [tex] 13\times cos(\frac{24}{26})[/tex]
= [tex] 13 \times 0.6034[/tex]
Speed along the line joining both = 7.84 meter/second