Answer :
Answer:
The magnitude and direction of its angular momentum relative to point is 115.28 kg m²/s.
Explanation:
Given that,
Mass = 2.00 kg
Velocity = 12.0 m/s
Suppose the distance from point O to point p and angle is 8.00 m and 36.9°.
We need to calculate the magnitude and direction of its angular momentum relative to point
Using formula of angular momentum
[tex]L=mvr\sin\theta[/tex]
Where, r = distance from point O to point P
v = speed
[tex]\theta[/tex] = direction
[tex]L=mvr\sin(180-\alpha)[/tex]
Put the value into the formula
[tex]L=2.00\times12.0\times8.00\sin(180-36.9)[/tex]
[tex]L=115.28\ kg\ m^2/s[/tex]
The direction of angular momentum is pointing into the page.
Hence, The magnitude and direction of its angular momentum relative to point is 115.28 kg m²/s.