Answer :
Answer:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408
Step-by-step explanation:
For this problem the sample size is large enough (n>30), and then the sampling distribution [tex]\hat p[/tex] would be approximately normal. The mean of the sampling distributions is given by [tex]p=0.52[/tex]
The expected value for the sampling distribution would be 0.52 since [tex]E(\hat p) = p[/tex]
And for the standard deviation we know that is given by:
[tex]Sd= \sqrt{\frac{p (1-p)}{n}}=\sqrt{\frac{0.52(1-0.52)}{150}}=0.0408[/tex]
So the correct answers on this case are:
a. The sampling distribution will be approximately normal.
d. The mean of the sampling distribution will be close to 52%
g. The standard deviation of the sampling distribution will be 0.0408