Answer :

luisejr77

Answer:

1) [tex]9\frac{1}{6}-8\frac{5}{6}=\frac{1}{3}[/tex]

2) [tex]10\frac{3}{4}-6\frac{4}{4}=3\frac{3}{4}[/tex]

Step-by-step explanation:

You can convert he mixed numbers to improper fractions:

1. Multiply the whole number part by the denominator of the fraction.

2. Add the product obtained to the numerator.

3. The denominator does not change.

Then:

[tex]9\frac{1}{6}=\frac{54+1}{6}=\frac{55}{6}\\\\8\frac{5}{6}=\frac{48+5}{6}=\frac{53}{6}\\\\10\frac{3}{4}=\frac{40+3}{4}=\frac{43}{4}\\\\6\frac{4}{4}=\frac{24+4}{4}=\frac{28}{4}[/tex]

Observe that, in each subtraction, the denominators are equal, then you can rewrite the denominator and subtract the numerators:

[tex]1)\ \frac{55}{6}-\frac{53}{6}=\frac{55-53}{6}= \frac{2}{6}=\frac{1}{3} \\\\2)\ \frac{43}{4}-\frac{28}{4}=\frac{43-28}{4}= \frac{15}{4}[/tex]

Divide 15 by 4. The quotient will be 3 and the remainder 3.

Then:

[tex]\frac{15}{4}=3\frac{3}{4}[/tex]

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