Answer :
Answer:
Plant c is [tex](\frac{16}{25})[/tex] times as tall as plant b.
Step-by-step explanation:
Here, the length of the plant b = [tex]6\frac{2}{3}[/tex] inches
Solving the mixed fraction, we get:
[tex]6\frac{2}{3} = \frac{(6 \times 3) + 2}{3} = \frac{20}{3}[/tex]
So, the length of plant b = [tex]\frac{20}{3}[/tex] inches
Also, the length of the plant c = [tex]4\frac{4}{15}[/tex] inches
Solving the mixed fraction, we get:
[tex]4\frac{4}{15} = \frac{(15 \times 4) + 4}{15} = \frac{64}{15}[/tex]
So, the length of plant c = [tex]\frac{64}{15}[/tex] inches
Now, let us assume that:
Plant c = K times as tall as plant b.
or, Length of plant c = K x ( Length of plant b)
[tex]\implies (\frac{64}{15}) = K \times (\frac{20}{3})\\\implies K = (\frac{64}{15}) \times (\frac{3}{20}) = (\frac{16}{25})\\\implies K = (\frac{16}{25})[/tex]
Hence, Plant c is [tex](\frac{16}{25})[/tex] times as tall as plant b.