Two people located 500 yards apart have spotted a hot air balloon. The angle of elevation from one person to the
balloon is 67°. From the second person to the balloon the angle of elevation is 46°. How high is the balloon when it
is spotted?

Answer :

Answer:

[tex] h =\sqrt{390.731^2 -152.671^2}=359.670 ft [/tex]

Step-by-step explanation:

The situation is illustrated on the figure attached.

We can begin finding the values for h1 and h2 and in order to do this we can use the sine law.

[tex] \frac{sin (67)}{h_2} = \frac{sin (67)}{500}[/tex]

From this we have that [tex] h_2 = 500[/tex]

And for h1 we have this:

[tex] \frac{sin(67)}{500} = \frac{sin(46)}{h_1}[/tex]

And we got [tex] h_1 = \frac{sin(46)}{sin(67)} 500= 390.731 ft[/tex]

Now we cna use the Pythagorean identity, since we have two right triangles. If we apply this identity to the right triangle on the left we have this:

[tex] h^2 + x^2 = h^2_1[/tex]  (1)

And for the right triangle we got:

[tex] h^2 +(500-x)^2 = h^2_2 [/tex]   (2)

We can subctract equation (2) and (1) and we got:

[tex] (500-x)^2 -x^2 = h^2_2 -h^2_1[/tex]

And if we apply some algebra we got this:

[tex] 250000 -1000 x +x^2 -x^2 = 97329.185[/tex]

[tex] 250000 -1000 x = 97329.185[/tex]

[tex] 1000 x = 152670.815[/tex]

[tex] x =152.671[/tex]

Now since we have the value of x we can find the value for h like this:

[tex] h^2 = h^2_1 -x^2[/tex]

[tex] h =\sqrt{390.731^2 -152.671^2}=359.670 ft [/tex]

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