Answer :
Answer:
y (max) = 4046 m
Step-by-step explanation:
h = 14*t² + 476*t is not the equation for a projectile upward movemente, since in that case projectile will continue going up to nfinite as time goes on. We must correct the equation according to projectile shot. Then
y = h = - 14*t² + 476 * t (1)
So we will have h maximum when V(y) = 0
then D(y)/dt = - 28 *t + 476
D(y)/dt = 0 ⇒ - 28 *t + 476 = 0 ⇒ t = 476 / 28
t = 17 sec
Then y maximum is for t = 17 plugging this value in equation (1) we get
y = - 14*t² + 476* t
y (max) = - 14* (17)² + 476 * ( 17) ⇒ y (max) = - 4046 + 8092
y (max) = 4046 m