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A picture has a height that is 4 / 3 its width. It is to be enlarged so that the ratio of height to width remains the same, but
the area is 192 in2. What are the dimensions of the enlargement?

Answer :

Dimensions of enlargement is height is 16 inch and width is 12 inch.

Step-by-step explanation:

A picture has a height that is 4 / 3 its width.

Let h be the height and w be the width.

Given that

                [tex]h=\frac{4}{3}w[/tex]

Area of picture is given by 192 inch²

            A = 192 inch²

          h x w = 192

     [tex]\frac{4}{3}w\times w=192\\\\\frac{4}{3}w^2=192\\\\w^2=144\\\\w=12inch\\\\h=\frac{4}{3}\times 12\\\\h=16inch[/tex]

Dimensions of enlargement is height is 16 inch and width is 12 inch.      

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