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In San Francisco a very simple technique is used to turnaround
a cable car when it reaches the end of its route. The carrolls onto
a turntable, which can rotate about a vertical axisthrough its
center. Then, two people push perpendicularly on thecar, one at
each end, as in the drawing. The turntable is rotatedone-half of a
revolution to turn the car around. If the length ofthe car is 7.00
m and each personpushes with a 180 N force, what is themagnitude of
the net torque applied to the car?

Answer :

skyluke89

The net torque applied to the car is [tex]1260 N\cdot m[/tex]

Explanation:

The torque exerted by a force applied perpendicular to the arm is given by:

[tex]\tau = Fd[/tex]

where

F is the magnitude of the force

d is the arm

In this problem, we have two forces of magnitude

F = 180 N

Each of them applied at each end of the car, therefore at a distance of

[tex]d=\frac{7.00 m}{2}=3.50 m[/tex]

from the centre of rotation of the car.

Therefore, the net torque applied to the car will be the sum of the two torques applied:

[tex]\tau = Fd + Fd = 2Fd=(2)(180)(3.50)=1260 N\cdot m[/tex]

Learn more about torque:

brainly.com/question/5352966

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