Answer :
Answer:
From Maxwell-Boltzmann distribution of molecules and their speeds,
average speed, Vavg = √([tex]\frac{8RT}{πM}[/tex])
and Root mean speed, Vrms = √([tex]\frac{3RT}{M}[/tex])
Given Vavg2 = 5Vrms1
Vavg2 = √([tex]\frac{8RT}{πM2}[/tex]) ................ eqn 1
Vrms1 = √([tex]\frac{3RT}{M1}[/tex]) --------------eqn 2
To find m1/m2, we divide eqn 1 by eqn 2,
we have, Vavg2/Vrms1 = √([tex]\frac{8m1}{3πm2}[/tex])
since Vavg2 = 5Vrms1, it becomes, 5 = √([tex]\frac{8m1}{3πm2}[/tex])
Therfore, m1/m2 = 25 * 3π/8 = 29.45
the mass ratio m1/m2 = 29.45.