Answer :
Answer:
The length of both the wires is 69 cm
Explanation:
It is given that,
Current flowing in each wire, [tex]I_1=I_2=22\ A[/tex]
Distance between wires, d = 25 cm = 0.25 m
Force exerted on each wire, [tex]F=2.7\times 10^{-4}\ N[/tex]
The force per unit length between two parallel wires carrying current is given by :
[tex]\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi d}[/tex]
l is the length of the wires
[tex]l=\dfrac{2\pi dF}{\mu_oI_1I_2}[/tex]
[tex]l=\dfrac{2\pi \times 0.25\times 2.7\times 10^{-4}}{4\pi \times 10^{-7}\times (22)^2}[/tex]
[tex]l=0.69\ m[/tex]
or
l = 69 cm
So, the length of both the wires is 69 cm. Hence, this is the required solution.