Answer :
Answer:
a) Bes
b) KF
c) MgO
d) H2S
e) AlCl3
f) NaI
g) SrSe
h) Ga2O3
Explanation:
In the picture attached the electron dot representation of different elements is shown.
a) From the picture it an be seen that Beryllium has 2 valence electrons, to form a ionic compound it will lost them and transforms into [tex]Be^{2+}[/tex]
Sulfur has 6 valence electrons, to form a ionic compound it will gain 2 electrons (to complete 8 electrons in its outer shell) and transforms into [tex]S^{2-}[/tex]
The ionic compounds are electrically neutral, so the charge combination of its ions must be zero. If we combine 1 [tex]Be^{2+}[/tex] cation with 1 [tex]S^{2-}[/tex] anion the net charge will be: +2 + (-2) = 0. Then the formula is BeS.
The other cases are solved analogously.
b)
potassium cation: [tex]K^{+}[/tex]
fluorine anion: [tex]F^{-}[/tex]
compound formula: KF (net charge: +1 + (-1) = 0)
c)
magnesium cation: [tex]Mg^{2+}[/tex]
oxygen anion: [tex]O^{2-}[/tex]
compound formula: MgO (net charge: +2 + (-2) = 0)
d) hydrogen and sulfur don't make an ionic compound, they form hydrogen sulfide which is a covalent compound
e) aluminum and chlorine form AlCl3, which is covalent.
f)
sodium cation: [tex]Na^{+}[/tex]
iodine anion: [tex]I^{-}[/tex]
compound formula: NaI (net charge: +1 + (-1) = 0)
g)
strontium cation: [tex]Sr^{2+}[/tex]
selenium anion: [tex]Se^{2-}[/tex]
compound formula: SrSe (net charge: +2 + (-2) = 0)
h)
gallium cation: [tex]Ga^{3+}[/tex]
oxygen anion: [tex]O^{2-}[/tex]
compound formula: Ga2O3 (net charge: 2*(+3) + 3*(-2) = 0)
To write the ionic formula of the compound, the cationic and anionic ions are combined with their charges.
(a) Beryllium and Sulfur:
Cation: [tex]\rm Be^2^+[/tex]
Anion = [tex]\rm SO_4^2^-[/tex]
The net charge = +2-2 = 0
Formula = [tex]\rm BeSO_4[/tex]
(b) Potassium and Fluorine
Cation = [tex]\rm K^+[/tex]
Anion = [tex]\rm F^-[/tex]
Net charge = 1-1 = 0
Formula = KF
(c) Magnesium and oxygen:
Cation = [tex]\rm Mg^2^+[/tex]
Anion = [tex]\rm O^2^-[/tex]
Net charge = +2 - 2 = 0
Formula = MgO
(d) Hydrogen and Sulfur :
Cation : [tex]\rm H^+[/tex]
Anion : [tex]\rm S^2^-[/tex]
To combine with 1 molecule of S and balance the net charge 0. 2 hydrogen ions are used.
Formula = [tex]\rm H_2S[/tex]
(e) Aluminium and Chloride:
Cation: [tex]\rm Al^3^+[/tex]
Anion : [tex]\rm Cl^-[/tex]
To combine with 1 molecule of Al and balance the net charge 0. 3 Cl ions are used.
Formula = [tex]\rm AlCl_3[/tex]
(f) Iodine and Sodium:
Cation: [tex]\rm Na^+[/tex]
Anion: [tex]\rm I^-[/tex]
Net charge: +1 - 1 = 0
Formula = NaI
(g) Selenium and strontium:
Cation: [tex]\rm Sr^2^+[/tex]
Anion: [tex]\rm Se^2^-[/tex]
Net charge = +2 - 2 = 0
Formual = SrSe
(h) Gallium and Oxygen:
Cation: [tex]\rm Ga ^3^+[/tex]
Anion: [tex]\rm O^2^-[/tex]
Net charge: 0
Formula : [tex]\rm Ga_2O_3[/tex]
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