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When the chemical equation is balanced what is the ratio of the coefficient of Ag(s) to the cofficient of H2O(l)?___Ag(s)+____NO3-(aq)+____H+(aq)→ ___Ag+(aq)+____NO(g)+______H2O(l)a. 1:1b. 2:1c. 3:1d. 3:2

Answer :

Answer:

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

Explanation:

Step 1: Balancing the equation

3 Ag (s) + 4 HNO3 (aq) → 3 AgNO3 (aq) + NO (g) + 2 H2O (l)

3 A g ( s )  +  4N O  ^3-  +  4 H +  → 3 A g + +3NO3- +   + N O  +  2 H 2 O

3 A g ( s )  +  N O  ^3-(aq)  +  4 H +(aq)  → 3 A g +(aq)   + N O(g)  +  2 H 2 O(l)

Step 2: The ratio between Ag(s) and H2O(l)

Ag(s):H2O(l)  = 3:2

For 3 moles Ag(s) we'll have 2 moles H2O(l)

Option D is correct

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