Answer :
The distance covered by the object is 42.4 m
Explanation:
The motion of the object is a uniformly accelerated motion (at constant acceleration), therefore we can use the following suvat equation:
[tex]v^2 -u^2 = 2as[/tex]
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the distance covered
For the object in this problem, we have:
u = 0 (it starts from rest)
v = 24 m/s (final velocity)
[tex]a=6.8 m/s^2[/tex]
Solving for s, we find the distance travelled by the object:
[tex]s=\frac{v^2-u^2}{2a}=\frac{24^2-0}{2(6.8)}=42.4 m[/tex]
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