Answer :
Answer:
a) 90 N
Explanation:
Coulomb's law: states that the electric force of attraction or repulsion between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them.
It is represented mathematically as
F = 1/4πε₀(q₁q₂)/d²......................... Equation 1
Where F = Electrostatic force, q₁ = charge on the first metal sphere, q₂ = charge on the second metal sphere, d = distance between the spheres, 1/4πε₀ = proportionality constant.
Given: q₁ = +2.0×10⁻⁵ C, q₂ = 2.0×10⁻⁵, d = 2.0×10⁻¹ m
Constant : 1/4πε₀ = 9×10⁹Nm²/C²
Substituting these values into equation 1,
F = (9×10⁹×2.0×10⁻⁵×2.0×10⁻⁵)/(2.0×10⁻¹)²
F = (9×4×10⁻¹)/4×10⁻²
F = 90 N
Therefore the electrostatic force is = 90 N
The right option is a) 90 N
In two small identical metal spheres, electrostatic force that the charge on sphere A exerts on the charge on sphere B is 90 N.
What is electric force?
Electric force is the force of attraction of repulsion between two bodies.
According to the Coulombs law, the force of attraction of repulsion between charged two bodies is directly proportional to the product of charges of them and inversely proportional to the square of distance between them.
It can be given as,
[tex]F=k\dfrac{q_1q_2}{r^2}[/tex]
Here, (k) is the coulombs constant, (q1 and q2) is the charges of two bodies and (r) is the distance between the two charges.
Here, two small identical metal spheres, A and B, on insulated stands, are each given a charge of +2.0 x 10-5 coulomb. The distance between the spheres is 2.0 x 10-1 meter.
Thus put the value in the above formula as,
[tex]F=9.10^9\dfrac{(2\times10^{-5}(2\times10^{-5}))}{(2\times10^{-1})^2}\\F=90\rm N[/tex]
Hence, the electrostatic force that the charge on sphere A exerts on the charge on sphere B is 90 N.
Learn more about the electric force here;
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