Answer :
The mass of bismuth fluoride formed is 41909.99 g
Explanation:
According to the law of conservation of mass, the total mass of the reactants in a chemical reaction must be equal to the total mass of the products after the reaction.
In this problem, we have:
- Reactants: bismuth and fluoride
- Products: bismuth fluoride
We also have:
- Mass of bismuth: 41796 g
- Mass of fluoride: 113.99 g
So, the total mass of the reactants is:
[tex]M=41796+113.99 =41909.99 g[/tex]
And therefore, the mass of bismuth fluoride formed is also 41909.99 g.
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