Answer:
a. 41.8 g; b. 1.18 mol
Explanation:
1. Mass of Cl
[tex]\text{Mass of Cl} = \text{80.3 g ZnCl}_{2} \times \dfrac{\text{52.02 g Cl}}{\text{100 g ZnCl}_{2}} = \text{41.8 g Cl}[/tex]
2. Moles of Cl
[tex]\text{Moles of Cl} = \text{41.8 g Cl} \times \dfrac{\text{1 mol Cl}}{\text{35.45 g Cl}} = \text{1.18 mol Cl}[/tex]
