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Find the solutions to the following linear-quadratic systems algebraically. Select the order pair that is one of the correct solutions from among the choices below.
y = -x² -x + 2
y = 2x + 2

(1, 0)
(3, 4)
(2, 0)
(-3, -4)

Answer :

calculista

Answer:

(-3, -4)

Step-by-step explanation:

we have

[tex]y=-x^{2} -x+2[/tex] ----> equation A

[tex]y=2x+2[/tex] ----> equation B

equate equation A and equation B

[tex]-x^{2} -x+2=2x+2[/tex]

[tex]-x^{2} -x+2-2x-2=0[/tex]

[tex]-x^{2} -3x=0[/tex]

[tex]x(x+3)=0[/tex]

The solutions of the quadratic equation are x=0 and x=-3

Find the values of y

For x=0

[tex]y=2(0)+2=2[/tex]

For x=-3

[tex]y=2(-3)+2=-4[/tex]

therefore

The solutions of the system are the points (0,2) and (-3,-4)

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