Answer :
Answer:
Explanation:
Given
For single guitar noise level [tex]SL=70\ dB[/tex]
Intensity of sound
Sound level[tex]=10\log (\frac{I}{I_0})[/tex]
where I=Intensity of sound Produced
[tex]I_0=[/tex]Human threshold frequency [tex](10^{-12}\ W/m^2)[/tex]
[tex]70=10\log (\frac{I}{10^{-12}})[/tex]
[tex]I=10^{-12}\times 10^7[/tex]
[tex]I=10^{-5}\ W/m^2[/tex]
For 2 guitars
[tex]I'=2I=2\times 10^{-5}\ W/m^2[/tex]
[tex]SL=10\log (\frac{I}{I_0})[/tex]
[tex]SL=10\log (\frac{2\times 10^{-5}}{10^{-12}})[/tex]
[tex]SL=10(7+\log (2))[/tex]
[tex]SL=73.01\ dB[/tex]