Initial velocity (u) = 0 m/s
Final velocity (v) = 25 m/s
time taken (t) = 10s
acceleration (a) = ?
Now,
Acceleration is rate of change of velocity, so formula is
a = (v - u)/t
a = (25 - 10)/10
a = 15/10
a = 1.5 m/(s^2)
Use this value of a.
The distance traveled by the car is 125 meters.
Given the following data:
To find the distance traveled by the car:
First of all, we would determine the acceleration of the car by using the following formula;
[tex]Acceleration = \frac{V \; -\; U}{t}\\\\Acceleration = \frac{25 \; -\; 0}{10}\\\\Acceleration = \frac{25}{10}[/tex]
Acceleration = 2.5 [tex]m/s^2[/tex]
Next, we would solve for the distance traveled by the car:
[tex]D = \frac{1}{2} at^2[/tex]
Substituting the values, we have:
[tex]D = \frac{1}{2} at^2\\\\D = \frac{1}{2} (2.5)(10^2)\\\\D = (1.25)(100)[/tex]
Distance, D = 125 meters.
Therefore, the distance traveled by the car is 125 meters.
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