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A space probe lands on the surface of a spherical asteroid 250 miles in a diamterer andmeasures the strenght of its gravitational fiels strength to be 4.95 x 10^-11. What is the mass of the asteroid?

Answer :

Answer:

Mass of asteroid will be [tex]M=3\times 10^{10}kg[/tex]

Explanation:

We have given diameter of the asteroid d = 250 miles

So radius [tex]R=\frac{250}{2}=125miles=125\times 1609.34=201167.5m[/tex]

Gravitational field strength [tex]g=4.95\times 10^{-11}m/sec^2[/tex]

Gravitational constant [tex]G=6.67\times 10^{-11}Nm^2/kg^2[/tex]

We know that [tex]g=\frac{GM}{R^2}[/tex], here M is the mass of asteroid

So [tex]4.95\times 10^{-11}=\frac{6.67\times 10^{-11}\times M}{201167.5^2}[/tex]

[tex]M=3\times 10^{10}kg[/tex]

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