Answer :
Answer:
Therefore the equation of the required line is y = [tex]\frac{-1}{2}[/tex]x + 2 or 2y + x = 4.
Step-by-step explanation:
i) when x = -2 then y = 3 so the line from x = -2 to x = 2 has the point (-2, 3)
ii)when x = 2 then y = 1 so the line from x = -2 to x = 2 has the point (2, 1)
iii) if two points in a line are given then slope of equation passing through the lines is given by
slope m = [tex]\frac{y_{2} - y_{1} }{x_{2} - x_{1} }[/tex] = [tex]\frac{1 - 3}{2 - (-2)}[/tex] = [tex]\frac{-2}{4}[/tex] = [tex]\frac{-1}{2}[/tex]
So from the general equation of a line y = mx + c
we get y = [tex]\frac{-1}{2}[/tex]x + c and substituting for x and y with (-2, 3) respectively we get
3 = 1 + c. Therefore c = 2.
Therefore the equation of the required line is y = [tex]\frac{-1}{2}[/tex]x + 2 or 2y + x = 4.