Answer:
[tex]\left\{\begin{array}{l}y_1=\log (2x+1)\\ \\y_2=3x-2\end{array}\right.[/tex]
Step-by-step explanation:
Given the equation
[tex]\log (2x+1)=3x-2[/tex]
This equation consists of two parts. In the left part, there is a logarithmic function [tex]y=log (2x+1)[/tex]
In the right part, there is a linear function [tex]y=3x-2[/tex]
To solve the equation graphically, you have to plot the graphs of these two functions and find the point of intersection of these graphs.
Hence, appropriate system is
[tex]\left\{\begin{array}{l}y_1=\log (2x+1)\\ \\y_2=3x-2\end{array}\right.[/tex]
