Answer :
Answer:
Option fraction 1 and 2 over 3 units is correct
Therefore [tex]Perimeter of a rectangle=1\frac{2}{3}[/tex]units
Step-by-step explanation:
Given rectangle of length is fraction 1 over 3 units and width is fraction 1 over 2 units
It can be written as [tex]l=\frac{1}{3}[/tex]units and [tex]w=\frac{1}{2}[/tex]units
To find the perimeter of a rectangle :
Perimeter of a rectangle=2(l+w)
Substitute the values of [tex]l=\frac{1}{3}[/tex]units and [tex]w=\frac{1}{2}[/tex]units in the above formula we get
[tex]Perimeter of a rectangle=2(\frac{1}{3}+\frac{1}{2})[/tex]
[tex]=2(\frac{1(2)+1(3)}{6})[/tex]
[tex]=2(\frac{2+3}{6})[/tex]
[tex]=\frac{5}{3}[/tex]
[tex]=1\frac{2}{3}[/tex]
Therefore [tex]Perimeter of a rectangle=1\frac{2}{3}[/tex]
Therefore option fraction 1 and 2 over 3 units is correct
Answer:
Option fraction 1 and 2 over 3 units
Step-by-step explanation: