Answer :
Answer:
Input power of the geothermal power will be 686000 J
Explanation:
We have given density of brine [tex]\rho =1050kg/m^3[/tex]
Rate at which brine is pumped [tex]V=0.3m^3/sec[/tex]
So mass of the pumped per second
Mass = volume × density = [tex]1050\times 0.3=315[/tex] kg/sec
Acceleration due to gravity [tex]g=9.8m/sec^2[/tex]
Depth h = 200 m
So work done [tex]W=mgh=315\times 9.8\times 200=617400J[/tex]
Efficiency is given [tex]\eta =0.9[/tex]
We have to fond the input power
So input power [tex]=\frac{617400}{0.9}=686000J[/tex]
So input power of the geothermal power will be 686000 J