Answer:
[tex]x=\frac{5t^2-a}{6-5t}[/tex]
Step-by-step explanation:
Given equation is
[tex]6x+a=5t(x+t)[/tex]
We have to make [tex]x[/tex] the subject of formula. That means we have to isolate [tex]x[/tex].
[tex]6x+a=5t(x+t)[/tex]
Distribute [tex]5t[/tex]
[tex]6x+a=5tx+5t^2[/tex]
Subtract [tex]a[/tex] both side we get,
[tex]6x+a-a=5xt+5t^2-a[/tex]
[tex]6x=5xt+5t^2-a[/tex]
Subtract [tex]5xt[/tex] both side we get,
[tex]6x-5xt=5xt-5xt+5t^2-a\\6x-5xt=5t^2-a[/tex]
Now, take [tex]x[/tex] common from left side of equation
[tex]x(6-5t)=5t^2-a[/tex]
Divide [tex]6-5t[/tex] both side,
[tex]\frac{x(6-5t)}{6-5t}=\frac{5t^2-a}{6-5t}\\\\x=\frac{5t^2-a}{6-5t}[/tex]