Answer :
Answer:
Brown color of the solution decreases
Explanation:
[tex]NO_2[/tex] is brown in color whereas [tex]N_2O_4[/tex] is colorless.
Equilibrium reaction between [tex]NO_2[/tex] and [tex]N_2O_4[/tex] is as follows:
[tex]2NO_2\leftrightharpoons N_2O_4[/tex]
As per the Le Chatelier's principle, if pressure of a equilibrium is increased, the equilibrium will shift in the direction having fewer no. of moles of gases.
In the given equilibrium, [tex]NO_2[/tex] side has more no. of moles. So on increasing pressure, equilibrium will shift towards the side of [tex]N_2O_4[/tex] or more formation of [tex]N_2O_4[/tex] will take place.
Therefore, more [tex]NO_2[/tex] will decompose that will decrease the brown color of the solution as [tex]N_2O_4[/tex] is colorless.