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On the Moon, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock has a speed v after falling from its point of release for a time t. Assuming that the rock does not hit the ground first, how fast will it be moving after it has fallen for a time 4t from its point of release?

Answer :

MechEngineer

Answer:

4v

Explanation:

If the rock has a speed v after falling from its point of release for a time t, we can calculate the gravitational acceleration on the moon:

[tex]v = g_mt[/tex]

[tex]g_m = v/t[/tex]

So after a time of 4t, its speed would be

[tex]v_{4t} = g_m4t = \frac{v}{t}4t = 4v[/tex]

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