Answer :
Answer:
Ella had 24 chocolate in her box originally.
Step-by-step explanation:
Given:
Let the total number of chocolates in the box be x
Number of chocolate given to her sister = [tex]\frac{1}{3}x[/tex]
Number of chocolates given to her brother = 4
Number of chocolates ate by her = 12
We need to find the total number of chocolates in the box
Solution:
Now we can say that;
the total number of chocolates in the box is equal to sum of Number of chocolate given to her sister, Number of chocolate given to her brother and Number of chocolates ate by her.
framing in equation form we get;
[tex]x=\frac{1}{3}x+4+12[/tex]
Combining like terms we get;
[tex]x-\frac{x}{3}=4+12\\\\x-\frac{x}{3}=16[/tex]
Now we will take LCM to make the denominator common we get;
[tex]\frac{3x}{3}-\frac{x}{3}=16[/tex]
Now Denominators are common so we will solve the numerators we get;
[tex]\frac{3x-x}{3}=16\\\\\frac{2x}{3}=16[/tex]
Now multiplying both side by [tex]\frac{3}{2}[/tex] we get;
[tex]\frac{3}{2}\times\frac{2x}{3}=16\times \frac{3}{2}\\\\x=24[/tex]
Hence Ella had 24 chocolate in her box originally.