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A child on a bridge throws a rock straight down to the water below. The point where the child released the rock is 82 m above the water and it took 1.3 s for the rock to reach the water. Determine the rock's velocity (magnitude

Answer :

Answer:

40 m/s

Explanation:

given,

height of the fall, h = 82 m

time taken to fall, t = 1.3 s

rock velocity, v = ?

acceleration due to gravity, g = 9.8 m/s²

rock is released initial velocity, u = 0 m/s

using equation of motion

v² = u² + 2 a s

v² = 0 + 2 x 9.8 x 82

v² = 1607.2

v = 40 m/s

hence, rock's velocity is equal to 40 m/s

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