Answered

A piece of clay sits 0.10 m from the center of a potter’s wheel. If the potter spins the wheel at an angular speed of 15.5 rad/s, what is the magnitude of the centripetal acceleration of the piece of clay on the wheel?

Answer :

Answer:

[tex]a=24.025\ m/s^2[/tex]    

Explanation:

Given that

Distance from the center ,r= 0.1 m

The angular speed ,ω = 15.5 rad/s

We know that centripetal acceleration is given as

a=ω² r

a=Acceleration

r=Radius

ω=angular speed

a=ω² r

Now by putting the values in the above equation we get

[tex]a=15.5^2\times 0.1\ m/s^2[/tex]

[tex]a=24.025\ m/s^2[/tex]

Therefore the acceleration of the clay will be [tex]a=24.025\ m/s^2[/tex].

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