Answer :
Answer:
Total work done in expansion will be [tex]3.60\times 10^5J[/tex]
Explanation:
We have given pressure P = 2.10 atm
We know that 1 atm [tex]=1.01\times 10^5Pa[/tex]
So 2.10 atm [tex]=2.10\times 1.01\times 10^5=2.121\times 10^5Pa[/tex]
Volume is increases from 3370 liter to 5.40 liter
So initial volume [tex]V_1=3.70liter[/tex]
And final volume [tex]V_2=5.40liter[/tex]
So change in volume [tex]dV=5.40-3.70=1.70liter[/tex]
For isobaric process work done is equal to [tex]W=PdV=2.121\times 10^5\times 1.70=3.60\times 10^5J[/tex]
So total work done in expansion will be [tex]3.60\times 10^5J[/tex]