Answer :
The current will double
Explanation:
The relationship between voltage and current in an electric circuit is given by the following equation (Ohm's law):
[tex]V=IR[/tex]
where
V is the voltage
I is the current
R is the resistance
making R the subject,
[tex]R=\frac{V}{I}[/tex]
Since in this experiment the resistance is kept constant, we can write:
[tex]\frac{V_1}{I_1}=\frac{V_2}{I_2}[/tex]
where
[tex]V_1=25 V[/tex] is the voltage in the 1st experiment
[tex]V_2=50 V[/tex] is the voltage in the 2nd experiment
[tex]I_1,I_2[/tex] are the currents in the 1st and 2nd experiment
We can re-arrange the equation as
[tex]\frac{I_2}{I_1}=\frac{V_2}{V_1}=\frac{50}{25}=2[/tex]
This means that the current will double in the 2nd experiment.
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