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A parking lot contains 100 cars, k of which happen to be lemons. We select m of these cars at random and take them for a test drive. Find the probability that n of the cars tested turn out to be lemons.

Answer :

Answer:

The probability that n of the cars tested turn out to be lemons is [tex]{m\choose n}\times\frac{k^{m}(100-k)^{(m-n)}}{100^{m}}[/tex].

Step-by-step explanation:

Let X = a car is lemon

There are 100 cars in a parking lot.

The probability that a car is a lemon is:

[tex]P (A\ car\ is\ lemons) = \frac{Number\ of\ cars\ that\ are\ lemons}{Total\ number\ of\ cars} =\frac{k}{100}[/tex]

The random variable [tex]X\sim Bin (100, \frac{k}{100})[/tex]

The probability function of a Binomial distribution is:

[tex]P(X=a)={a\choose b}\times p^{b}\times (1-p)^{a-b}[/tex]

Number of cars selected is a = m.

Compute the probability that out of m cars n turn out to be lemons as follows:

[tex]P(X=n)={m\choose n}\times [\frac{k}{100}] ^{n}\times (1-\frac{k}{100} )^{m-n}={m\choose n}\times\frac{k^{m}(100-k)^{(m-n)}}{100^{m}}[/tex]

Thus, the probability that out of m cars n turns out to be lemons is [tex]{m\choose n}\times\frac{k^{m}(100-k)^{(m-n)}}{100^{m}}[/tex].

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