A 0.500 kg mass is oscillating on a
spring with k = 330 N/m. The total
energy of its oscillation is 3.24 J.
What is the maximum speed of
the mass?
(Unit = m/s)​

Answer :

thobee600

Answer: E = kA2/2 ⇒

 

A = √(2E/k) = √[2(3.24)/330] m = ? m  

Explanation: Equate the elastic potential energy at the amplitude to the total energy of the mass.  The answer will not depend on the mass.  

 

Answer:

3.6

Explanation:

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