Answer :
Answer:
Step-by-step explanation:
Given to ask the Teacher Write out the form of the partial fraction decomposition of the function
It is not necessary to find the coefficients
For decomposition of partial fractions the necessary condition is that the denominator should be in a position to be factored into atleast two factors.
Then only partial fraction is possible otherwise not.
Here
a) [tex]\frac{x}{x^2+x-20}[/tex]
Denominator = [tex]x^2+x-20\\=(x+5)(x-4)[/tex]
So this can be resolved into partial fractions as
[tex]\frac{x}{x^2+x-20}=\frac{A}{x+5}+ \frac{B}{x-4}[/tex]
b) Here given
[tex]\frac{x^2}{x^2+x+2} \\=\frac{x^2+x+2-x-2}{x^2+x+2} \\=1-\frac{x+2}{x^2+x+2}[/tex]
But denominator cannot be factored
So cannot be decomposed into partial fraction
DNE